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Q: What number has 9 thousands 7 fewer hundreds than thousands 1 fewer tens than hundreds and 8 fewer ones than thousands?

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4117

7252

8806

The number is 8,413

6,130 has.

It is 5305.

3896

7252

Having: 9 ten-thousands → 90,000 the same number of thousands as ten thousands → 9 ten-thousands: 9 thousands → 9,000 8 fewer hundreds than ten-thousands → 9 ten-thousand: 9 - 8 = 1 hundreds → 100 6 more tens than hundreds → 1 hundreds: 1 + 6 = 7 tens → 70 6 fewer ones than thousands → 9 thousands: 9 - 6 = 3 ones → 3 → the number is 90,000 + 9,000 + 100 + 70 + 3 = 99,173.

80,557

7641

8499

The number has 1 thousand. It has 8 more hundreds than thousands so it has 8 more hundreds than 1. That is, it has 9 hundreds. It has 1 fewer tens than hundreds so it has 1 fewer tens than 9. That is, it has 8 tens.It has 2 fewer ones than tens so it has 2 fewer ones than 8. That is, it has 6 ones. So the number is 1986.

It is 4692.

It is 7414

2 thousands: 2 × 1000 - 2,000 1 fewer hundreds than thousands: 2 - 1 = 1 hundred: 1 × 100 = 100 4 more tens than hundreds: 1 + 4 = 5 tens: 5 × 10 = 50 same number of ones as thousands: 2 ones: 2 × 1 = 2 → the number is 2000 + 100 + 50 + 2 = 2152.

977

what number has 9 hundreds, 2 fewer tens than hundreds, and 2 fewer ones than hundreds

Any number ending with 9417.

952

2230

521

530?

The number is 729.

There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }

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